5b^2+29b+20=0

Solution for 5b^2+29b+20=0 equation:

Simplifying
5b2 + 29b + 20 = 0

Reorder the terms:
20 + 29b + 5b2 = 0

Solving
20 + 29b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(5 + b)(4 + 5b) = 0

Subproblem 1
Set the factor '(5 + b)' equal to zero and attempt to solve:

Simplifying
5 + b = 0

Solving
5 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + b = 0 + -5

Combine like terms: 5 + -5 = 0
0 + b = 0 + -5
b = 0 + -5

Combine like terms: 0 + -5 = -5
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(4 + 5b)' equal to zero and attempt to solve:

Simplifying
4 + 5b = 0

Solving
4 + 5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 5b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 5b = 0 + -4
5b = 0 + -4

Combine like terms: 0 + -4 = -4
5b = -4

Divide each side by '5'.
b = -0.8

Simplifying
b = -0.8
Solution
b = {-5, -0.8}